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22.1 Elasto-Plastic Damage Model

The Maekawa Concrete model is derived from two-dimensional and three-dimensional cyclic loading data. The derivation uses four material parameters (K , F , H , and D ) for concrete with normal aggregate and strength ranging from 15 MPa to 50 MPa.

Once the elastic strain vector has been determined, then the so-called fracture parameter K is calculated as a function of the invariants of the elastic strain tensor and a number of elastic parameters. Due to damage it is assumed that the shear modulus will be reduced by a factor K , i.e., the initial shear modulus G is multiplied with K . Factor K runs from 1 to 0, where 0 stands for complete deterioration and 1 for no damage. To determine the actual damage shear modulus the actual stresses and the elastic-moduli matrix of damaged concrete are formulated as a function of the damage parameter K , the invariants of the elastic strain tensor, and a number of material parameters. These relations are defined by Meakawa et. al [66,67,68] as:

K = K(F) = exp$\displaystyle \left(\vphantom{ - \frac{ F }{ 3.25 } \left( 1 - \exp \left( - \frac{ F }{ 0.8 } \right) \right) }\right.$ - $\displaystyle {\frac{{ F }}{{ 3.25 }}}$$\displaystyle \left(\vphantom{ 1 - \exp \left( - \frac{ F }{ 0.8 } \right) }\right.$1 - exp$\displaystyle \left(\vphantom{ - \frac{ F }{ 0.8 } }\right.$ - $\displaystyle {\frac{{ F }}{{ 0.8 }}}$$\displaystyle \left.\vphantom{ - \frac{ F }{ 0.8 } }\right)$$\displaystyle \left.\vphantom{ 1 - \exp \left( - \frac{ F }{ 0.8 } \right) }\right)$$\displaystyle \left.\vphantom{ - \frac{ F }{ 3.25 } \left( 1 - \exp \left( - \frac{ F }{ 0.8 } \right) \right) }\right)$ (22.1)
F = F$\displaystyle \left(\vphantom{ I_{\mathrm{1e}}, J_{\mathrm{2e}}, J_{\mathrm{3e}} }\right.$I1e, J2e, J3e$\displaystyle \left.\vphantom{ I_{\mathrm{1e}}, J_{\mathrm{2e}}, J_{\mathrm{3e}} }\right)$    
           = $\displaystyle {\frac{{ \sqrt{2} \, J_{\mathrm{2e}} }}{{ 0.23 \, \varepsilon _{0} - \sqrt{3} \, I_{\mathrm{1e}} }}}$ x $\displaystyle {\frac{{ 1 }}{{ 5 }}}$$\displaystyle \left(\vphantom{ \frac{ 3 \sqrt{3} }{ 2 } \left( \frac{ J_{\mathrm{3e}} }{ J_{\mathrm{2e}} } \right)^{\!3} + 6 }\right.$$\displaystyle {\frac{{ 3 \sqrt{3} }}{{ 2 }}}$$\displaystyle \left(\vphantom{ \frac{ J_{\mathrm{3e}} }{ J_{\mathrm{2e}} } }\right.$$\displaystyle {\frac{{ J_{\mathrm{3e}} }}{{ J_{\mathrm{2e}} }}}$$\displaystyle \left.\vphantom{ \frac{ J_{\mathrm{3e}} }{ J_{\mathrm{2e}} } }\right)^{{\!3}}_{}$ + 6$\displaystyle \left.\vphantom{ \frac{ 3 \sqrt{3} }{ 2 } \left( \frac{ J_{\mathrm{3e}} }{ J_{\mathrm{2e}} } \right)^{\!3} + 6 }\right)$ (22.2)
H = H(J2e) = $\displaystyle {\frac{{ 9 }}{{ 10 }}}$ b $\displaystyle \varepsilon_{{0}}^{}$$\displaystyle \left(\vphantom{ \frac{ J_{\mathrm{2e}} }{ \varepsilon _{0} } }\right.$$\displaystyle {\frac{{ J_{\mathrm{2e}} }}{{ \varepsilon _{0} }}}$$\displaystyle \left.\vphantom{ \frac{ J_{\mathrm{2e}} }{ \varepsilon _{0} } }\right)^{{\!3}}_{}$ (22.3)
D = D(I1e, K)    
           = $\displaystyle \left(\vphantom{ \frac{ -1 + 2 \nu }{ \sqrt{3} \, ( 1 + \nu ) } \...
...repsilon _{0} }{ 0.28 \, \varepsilon _{0} } \left( 1 - 4 K^{2} \right) }\right.$$\displaystyle {\frac{{ -1 + 2 \nu }}{{ \sqrt{3} \, ( 1 + \nu ) }}}$ 4K2 + $\displaystyle {\frac{{ \sqrt{2} \, I_{\mathrm{1e}} + 0.38 \, \varepsilon _{0} }}{{ 0.28 \, \varepsilon _{0} }}}$$\displaystyle \left(\vphantom{ 1 - 4 K^{2} }\right.$1 - 4K2$\displaystyle \left.\vphantom{ 1 - 4 K^{2} }\right)$$\displaystyle \left.\vphantom{ \frac{ -1 + 2 \nu }{ \sqrt{3} \, ( 1 + \nu ) } \...
...repsilon _{0} }{ 0.28 \, \varepsilon _{0} } \left( 1 - 4 K^{2} \right) }\right)$ (22.4)

Scalars I1e , J2e , and J3e respectively are the first, second, and third elastic strain invariants:

I1e = $\displaystyle {\frac{{1}}{{3}}}$$\displaystyle \varepsilon_{{\mathrm{e}ii}}^{}$ (22.5)

J2e = $\displaystyle \sqrt{{\frac{1}{2} \, e_{\mathrm{e}ij} \, e_{\mathrm{e}ij}}}$ (22.6)

J3e = $\displaystyle \sqrt[3]{{\frac{1}{3} \, e_{\mathrm{e}ij} \, e_{\mathrm{e}jk} \, e_{\mathrm{e}ki}}}$ (22.7)

with

eeij = $\displaystyle \varepsilon_{{\mathrm{e}ij}}^{}$ - $\displaystyle \delta_{{ij}}^{}$I1e (22.8)

being the elastic deviatoric tensor and $ \varepsilon_{{\mathrm{e}ij}}^{}$ the elastic strain tensor. Equations (22.1) to (22.4) include the material constant $ \varepsilon_{{0}}^{}$ which was adopted as a function of the compressive strength fc , Young's modulus E , and Poisson's ratio $ \nu$ :

$\displaystyle \varepsilon_{{0}}^{}$ = 1.6 (1 + $\displaystyle \nu$$\displaystyle {\frac{{ f_{\mathrm{c}} }}{{ E }}}$ (22.9)

so that these material functions would be applicable to concrete of normal aggregate a1Gnd strength.

The fracture function K [Eq.(22.1)] represents the degradation of the shear elastic strain energy of concrete including defects. The parameter F [Eq.(22.2)] is the indicator (equivalent elastic strain) to express the macroscopic intensity of internal stress which advances the damage under an arbitrary level of confinement (F = 0 and $ \dot{{F}}$ > 0 ). The function H [Eq.(22.3)] indicates the plastic hardening of the internal plastic element in the damaged concrete, with b being the user-defined correction factor for plastic evolution, which has a default value of 1.0. The derivative D [Eq.(22.4)] indicates the plastic dilatancy induced by the shear plastic dislocation along the internal defects.


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DIANA-9.3 User's Manual - Material Library
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